Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . suppose 23. g of ethane is mixed with 147. g of oxygen. calculate the minimum mass of ethane that could be left over by the chemical reaction. be sure your answer has the correct number of significant digits.
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Ответ:
The minimum mass of ethane that could be left over by the chemical reaction is zero.
Explanation:
Moles of ethane =
Moles of oxygen gas :
Since, 2 moles of ethane gas react with 7 moles of oxygen gas.
Then 0.7666 mol of ethane gas will react wit:
This means that ethane gas is in limited amount.hence ethane is a limiting reagent. Where as oxygen in present in excessive amount.
All the moles ethane gas will go under combustion reaction leaving zero moles behind.
Ответ:
628
Step-by-step explanation:
1) Find the circumference of the wheel (the distance it travels in 1 revolution)
where d is the diameter
Plug in 2 ft as the diameter
Therefore, the circumference of the wheel is 6.28 ft.
2) Multiply the circumference by 100
6.28 × 100
= 628 ft
Therefore, Joe would travel 628 feet if his wheel turns exactly 100 complete revolutions in one direction.
I hope this helps!