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24.02.2020 •
Chemistry
How many formula units of sodium nitrate will react with 25.0g of calcium carbonate to produce sodium carbonate and calcium nitrate
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Ответ:
Complete Question:
How many formula units of sodium nitrate will react with 25.0 g of calcium carbonate to product sodium carbonate and calcium nitrate according to the following reactions?
2 Na(NO3) + Ca(CO3) → Na2(CO3) + Ca(NO3)2
Explanation:
Given chemical equation:
Given mass of calcium carbonate = 25 g
We need to determine the number of formula units of sodium nitrate that will react with 25 g of calcium carbonate.
Step 1: To calculate the number of moles of Calcium carbonate
Number of mole is the ratio of mass to the molar mass, given as
molar mass of calcium carbonate = 100.0869 g / mol
Step 2: Moles of Sodium nitrate that reacted
From the equation, 2 moles of NaNO₃ reacts with 1 mole of CaCO₃
Thus, the mole ratio of NaNO₃ to CaCO₃ is 2 : 1
Therefore; Number of moles of NaNO₃ = Moles of CaCO₃ × 2
Number of moles of NaNO₃ = 0.25 × 2 = 0.5 moles
Step 3: Calculate formula units of NaNO₃
We need to know that 1 mole of a compound contains formula units equivalent to the Avogadro's constant.
1 mole of a compound contains
formula units
Therefore; 0.5 moles of NaNO₃ will have;
= 0.5 ×
formula units
= 3.011
formula units
Ответ:
The average's about 63.62.
i hope my answer helped you. Have a nice day!