How many moles of oxygen atoms (not molecules) are present in 6.41×1025 molecules
of dinitrogen pentoxide (N2O5)?
1. 532 mol
2. 106 mol
3. 32 × 1025 mol
4. 266 mol

532 moles of O atoms.

Explanation:

Given data:

Number of moles of oxygen atom present = ?

Number of molecules of N₂O₅= 6.41×10²⁵ molecules

Solution:

First of all we will calculate the number of moles of N₂O₅.

1 mole = 6.022×10²³ molecules

6.41×10²⁵ molecules × 1 mol /6.022×10²³ molecules

106.4 mol

Number of atoms of O:

1 mole of N₂O₅ contain 5 moles of O atoms.

106.4×5 = 532 mol

If the products contain 3 nitrogen atoms, then so did the reactants since overall mass is conserved in a chemical reaction.

Explanation: