How many O atoms are in 4C₆H₁₂O₆

Number of O atoms : 24

Given

C₆H₁₂O₆ compound

Required

Number of atoms

Solution

A molecular formula  shows the number of atomic elements in compound.  

The empirical formula is the smallest comparison of the atoms

Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.

The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules

So number of O atoms :

= 4 x 6 = 24 atoms

For A: The chemical equation is

For B: The enthalpy of the reaction is 71.5 kJ/mol

Explanation:

Decomposition reaction is defined as the reaction in which a single chemical substance breaks down into two or more smaller substances.

The chemical equation for the decomposition of zinc carbonate follows:

Endothermic reactions are defined as the reactions in which energy is absorbed in the reaction. The enthalpy change of the reaction is positive.

Exothermic reactions are defined as the reactions in which energy is released in the reaction. The enthalpy change of the reaction is negative.

In the above reaction, the heat is added. So, the reaction is endothermic in nature.

Amount of heat added per mole of zinc carbonate = 71.5 kJ

Hence, the enthalpy of the reaction is 71.5 kJ/mol