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BradFarquharson1105
22.11.2020 •
Chemistry
How much of glucose (C6H1206) is needed to make 1 L of a 1-M solution? Use details to support your answer.
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Ответ:
200 g C₆H₁₂O₆
General Formulas and Concepts:
Chemistry - Solutions
Reading a Periodic TableUsing Dimensional AnalysisMolarity = moles of solute / liters of solutionExplanation:
Step 1: Define
1 M C₆H₁₂O₆
1 L of solution
Step 2: Identify Conversions
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
Step 3: Find moles of solute
1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L
x = 1 mol C₆H₁₂O₆
Step 4: Convert
Step 5: Check
We are given 1 sig figs. Follow sig fig rules and round.
180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆
Ответ:
Cl2C=CCl2
Explanation: