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pamelperezz26
22.03.2020 •
Chemistry
If 0.500 mole of calcium carbonate is produced in a particular reaction, how many moles of sodium chloride are produced in the same reaction?
CaCl2 (aq) + Na2CO3 (aq) → CaCO3 (s) + 2 NaCl (aq)
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Ответ:
In the same reaction, 1.00 moles of NaCl are produced
Explanation:
Step 1: Data given
Number of moles calcium carbonate = 0.500 moles
Step 2: The balanced equation
CaCl2 (aq) + Na2CO3 (aq) → CaCO3 (s) + 2 NaCl (aq)
Step 3: Calculate moles sodium chloride (NaCl)
For 1 mol CaCl2 we need 1 mol Na2CO3 to produce 1 mol CaCO3 and 2 moles NaCl
For 0.500 moles CaCO3 produced we we'll have 2* 0.500 = 1.00 mol of NaCl produced
In the same reaction, 1.00 moles of NaCl are produced
Ответ: