If 37.4 grams of water decompose at 297 kelvin and 1.30 atmospheres, how many liters of oxygen gas can be produced? show all of the work used to solve this problem. 2h2o (l) yields 2h2 (g) + o2 (g)

To determine the liters of oxygen gas, we convert the 37.4 grams of water to moles, which is 2. 078 moles. The moles oxygen is half the moles of water which is equal to 1.039 moles. Using ideal gas equation, PV=nRT, we get the volume from the given temperature and pressure. The volume is 19.49 liters.

Glucose + oxygen = Water + carbon dioxide + energy