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samueldfhung
29.03.2020 •
Chemistry
Lysine, which is an essential amino acid, contains only C, H, N, and O. In one
experiment, the complete combustion of 2.175 g of lysine produces 3.93 g of CO2
and 1.87 g of H2O. In a separate experiment, 1.873 g of lysine produces 0.436 g of
NH3. What is the empirical formula of lysine?
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Ответ:
The empirical formula is C3H7NO
Explanation:
Step 1: Data given
Mass of the lysine sample in the first experiment = 2.175 grams
Mass of CO2 produced = 3.93 grams
Mass of H2O produced = 1.87 grams
Molar mass CO2 = 44.01 g/mol
Molar mass H2O = 18.02 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass O = 16.0 g/mol
Atomic mass H = 1.01 g/mol
In a separate experiment, 1.873 g of lysine produces 0.436 g of NH3
Molar mass NH3 = 17.03 g/mol
Step 2: Calculate moles CO2
Moles CO2 = mass CO2 / molar mass CO2
Moles CO2 = 3.93 grams / 44.01 g/mol
Moles CO2 = 0.0893 moles
Step 3: Calculate moles C
For 1 mol CO2 we have 1 mol C
For 0.0893 moles CO2 we have 0.0893 moles C
Step 4: Calculate mass C
Mass C = 0.0893 moles * 12.01 g/mol
Mass C = 1.072 grams
Step 5: Calculate moles H2O
Moles H2O = 1.87 grams / 18.02 g/mol
Moles H2O = 0.104 moles
Step 6: Calculate moles H
For 1 mol H2O we have 2 moles H
For 0.104 moles H2O we have 0.208 moles H
Step 7: Calculate mass H
Mass H = 0.208 moles * 1.01 g/mol
Mass H = 0.210 grams
Step 8: Calculate mass %
Mass % C = (1.072 grams / 2.175 grams) * 100%
MAss % C = 49.3 %
Mass % H = (0.210 grams / 2.175 grams ) * 100 %
Mass % H = 9.66 %
Step 9: Calculate moles NH3
Moles NH3 = 0.436 grams / 17.03 g/mol
Moles NH3 = 0.0256 moles
Step 10: Calculate moles N
For 1 mol NH3 we have 1 mol N
For 0.0256 moles NH3 we have 0.0256 moles N
Step 11: Calculate mass N
Mass N = 0.0256 grams * 14.0 g/mol
Mass N = 0.358 grams
Step 12: Calculate mass C in Lysine
MAss C = 0.493 * 1.873 grams
Mass C = 0.923 grams
Step 13: Calculate mass H
Mass H = 0.0966 * 1.873 grams
Mass H = 0.181 grams
Step 14: Calculate mass O
Mass O = 1.873 grams - 0.923 grams - 0.181 grams - 0.358 grams
MAss O = 0.411 grams
Step 15: Calculate moles in the compound
Moles C = 0.923 grams / 12.01 g/mol
Moles C = 0.07685 moles
Step 16: Calculate moles H
Moles H = 0.181 grams / 1.01 g/mol
Moles H = 0.1792 moles
Step 17: Calculate moles N
Moles N = 0.358 grams / 14.0 g/mol
Moles N = 0.02557 moles
Step 18: Calculate moles O
Moles O = 0.411 grams / 16.0 g/mol
Moles O = 0.02569 moles
Step 19: Calculate the mol ratio
We divide by the smallest amount of moles
C: 0.07685 moles / 0.02557 moles = 3
H: 0.1792 moles / 0.02557 moles = 7
N: 0.02557 moles / 0.02557 moles = 1
O: 0.02569 moles / 0.02557 = 1
The empirical formula is C3H7NO
Ответ:
How to Find Gram Molecular Mass
1. Look up the relative atomic mass of each element in the formula.
2. Multiply the subscript after each element symbol (the number of atoms) by that element's atomic mass. ...
3. Add all of the values together to find the gram molecular mass.
Explanation: