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See the answers below

Explanation:

13.5 g of NH4Cl was dissolved in 315 mL of water.

Moles of NH4Cl present in the solution = mass/molar mass

Molar mass of NH4Cl = 54.49 g/mol

a) Moles of NH4Cl = 13.5/54.49

            = 0.25 mole

b) Molarity of solution = moles of solute/volume of solution

moles of NH4Cl = 0.25

volume of solution = 315 mL = 0.315 L

molarity = 0.25/0.315

             = 0.79 M

c) moles required = 0.0500 mole

molarity = 0.79 M

molarity = moles x volume

volume = molarity/moles

         = 0.79/0.0500

         = 15.8 L = 15,800 mL