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sharondacarruth7853
16.12.2019 •
Chemistry
Ozone molecules in the stratosphere absorb much of the harmful radiation from the sun. typically, the temperature and partial pressure of ozone in the stratosphere are 250 k and 0.001 atm, respectively. how many grams of ozone are present in 1000 liters of air under these conditions? (assume ideal-gas behavior)
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Ответ:
2.35 g of ozone are present
Explanation:
From Ideal gas equation,
PV = nRT equation 1
P = pressure of the ozone, n = number of mole of the ozone molecule, R = molar gas constant, V = volume of the ozone, T = Temperature.
making n the subject of the
n = PV/RT equation 2
Where V = 1000 dm³, P = 0.001 atm, T = 250 K, R = 0.082 atm/(dm³Kmol)
Substituting these values into equation 2
n = (1000×0.001)/(0.082×250)
n = 1/20.5
n = 0.049 mole.
Number of mole = Reacting mass/ molar mass .
Molar mass of ozone gas (O₃) = 48 g/mol
Mass of Ozone = 48 × 0.049
Mass of ozone = 2.35 g.
Therefore, 2.35 g of ozone are present.
Ответ:
Sample Response: The nucleus of an atom has a positive charge because the proton is positive and the neutron is neutral.
Explanation: