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23.04.2020 •
Chemistry
Percent yield for iron (III) oxide is 6.37 moles of iron (III) bromide yielded 1.84 oles of iron (III) sulfide
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Ответ:
320 gm
Explanation:
4 Fe + 3 O2 > 2 Fe2O3 How many moles of iron(III) oxide, Fe2O3 , will be produced if 4 moles of iron, Fe, are consumed
for every 4 moles of Fe, 2 moles of Fe2O3 are produced.
Fe2O3 has a molar mass of (56 X 2) + (16 X 3) = 112 + 48 =160
160 X 2 =320 gm