Propionoic acid, c3h6o2, reacting with methanol, ch4o, will produce c4h8o2 and water. if 70.0 g of propionoic acid and 60.0 g of methanol are reacted together, which one will be the limiting reactant?
c3h6o2 + ch4o → c4h8o2 + h2o

First, find the molar masses of each substance.

C3H6O2 = 74 g/mol

CH4O = 32 g/mol

Then, use the molar mass to find how many moles of each are present:

C3H6O2:  

CH4O:  

There is a higher number of moles of CH4O than C3H6O2, so the C3H6O2 will run out faster.  Therefore, C3H6O2 is the limiting reactant.

The reduction in the temperature leads to an automatic decrease in the pressure of the gas inside the he container. This is due to the decreased number of collisions per unit area of the container walls. Pressure law states that at constant volume, the pressure of a fixed mass of a gas is directly proportional to the absolute temperature.