SO2 +
Li2Se → __SSe2 +
Li2O

We want to take inventory of the right and left side Right: S=1 O = 2 Li = 2 Se= 1 Left: S= 1 Se=2 Li= 2 O=1Lets balance out each side because we see we are off by 1 oxygen on the left Add a coefficient of 2 on the Li2OAdd a coefficient of 2 on the right Li2Se Now we have So2+ 2Li2Se ---> SSe2+ 2Li2O

0.61 L

Explanation:

T1 = 23.0 +273 = 296K

T2 = 57+273 = 330 K

V2 = (V1×T2)/T1

V2 = (0.55 × 330)/296

V2 = 0.61 L