The electron configuration below represents a ground-state atom of which element? 1s22s22p63s23p4

The given electronic configuration has been representing the ground state of sulfur atom.

The electronic configuration has been the electron address in an atom. It has been the representation of the number of electrons present in the quantum subshell of each shell.

The number of electrons has been calculated with the superscript of each quantum level. The number of  electrons in the given electronic configuration has been given as:

The number of electrons in the sample has been a representation of the atomic number of the element. The number of electrons in the given sample has been 16. Thus, the atomic number of the sample has been 16.

The element with 16 atomic number is Sulfur. Thus, the given electronic configuration has been representing the ground state of sulfur atom.

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The electron configuration below represents a ground-state atom of which element? 1s22s22p63s23p4

Sulfur

Explanation:

There are two ways to get the answer.

1. Count the electrons.

The electron configuration is 1s² 2s²2p⁶ 3s²3p⁴.

The numbers in the superscripts tell you how many electrons are in each subshell.

They add up to 16, and element 16 is sulfur.

2. Look at the outermost shell.

The outermost shell has the electron configuration 3s²3p⁴.

This tells you that the element is in Period 3 and has six valence electrons.

Start at the left of Period 3 (Na). Count six places to the right, and  you come to sulfur.

The question is typed wrong. The correct question is

Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3.

Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + CaSO4

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Al2(SO4)3 + 3 Ca(OH)2 = 2 Al(OH)3 + 3 CaSO4

3: 2

Explanation:-

Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + CaSO4

In the left hand side there are 3 S atoms from Al2(SO4)3

But in the right side there is only 1 S from CaSO4.

To make the right side same we multiply the CaSO4 by 3.

Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + 3 CaSO4

Now in the right side there 3 Ca from 3 CaSO4.

But in the left side there is only 1 Ca from Ca(OH)2.

To make it same we multiply Ca(OH)2 by 3.

Al2(SO4)3 + 3 Ca(OH)2 --> Al(OH)3 + 3 CaSO4

Now there 2 Al from Al2(SO4)3 on the left.

But there is only 1 Al from Al(OH)3.

So we multiply Al(OH)3 by 2.

Al2(SO4)3 + 3 Ca(OH)2 --> 2 Al(OH)3 + 3 CaSO4

Now we have 12 + 6 = 18 O on the left.

On the right we have 6 + 12 = 18 O atoms.

On the left we have 6 H atoms.

On the right we have 6 H atoms.

So our equation is balanced.

From the balanced equation

Al2(SO4)3 + 3 Ca(OH)2 --> 2 Al(OH)3 + 3 CaSO4

Ratio of Ca(OH)2 to Al(OH)3 = 3 : 2