The following information is given for benzene, C6H6, at 1atm: boiling point = 80.1 °C Hvap(80.1 °C) = 30.7 kJ/mol specific heat liquid = 1.74 J/g°C At a pressure of 1 atm, what is H in kJ for the process of condensing a 24.8 g sample of gaseous benzene at its normal boiling point of 80.1 °C. kJ
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Ответ:
The heat required for the process is 4.24 kJ
Explanation:
To calculate the number of moles, we use the equation:
Given mass of benzene = 24.8 g
Molar mass of benzene = 78.11 g/mol
Putting values in above equation, we get:
To calculate the enthalpy change of the reaction, we use the equation:
where,
= amount of heat absorbed = ?
n = number of moles = 0.318 moles
= enthalpy change of the reaction = 30.7 kJ/mol
Putting values in above equation, we get:
Hence, the heat required for the process is 4.24 kJ
Ответ: