The reaction 3 A + 2 B + 4 C → products is known to be second order in A, first order in B and independent of the concentration of C. What is the value of the rate constant for this reaction if its rate is 0.771 M · s−1 when [A] = 5.00 M, [B] = 7.00 M, and [C] = 3.00M?Answer in units of M−2· s−1.

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Ответ:

kyleereeves2007

11.05.2022

Chemistry

8) $\displaystyle 9,4 ≈ hypotenuse \\ 4,9 ≈ leg$

6) $\displaystyle 5,2 ≈ horizontal\:leg \\ 4,7 ≈ reflexive, vertical\:leg$

5) $\displaystyle 3,2 ≈ reflexive, vertical\:leg$

Step-by-step explanation:

Obviously, use the Pythagorean Theorem for all of them:

8) $\displaystyle -5^2 + 7^2 = c^2 → -25 + 49 = c^2 → \sqrt{24} = \sqrt{c^2} → 2\sqrt{6} = c → 4,898979486 ≈ 4,9 ≈ c \\ \\ 5^2 + 8^2 = c^2 → 25 + 64 = c^2 → \sqrt{89} = c^2 → 9,433981132 ≈ c$

6) $\displaystyle -5,2^2 + 7^2 = c^2 → -27,04 + 49 = c^2 → \sqrt{21,96} = \sqrt{c^2} → \frac{3\sqrt{61}}{5} = c → 4,686149806 ≈ 4,7 ≈ c$

5) $\displaystyle -3,8^2 + 5^2 = c^2 → -11,44 + 25 = c^2 → \sqrt{10,56} = \sqrt{c^2} → \frac{2\sqrt{66}}{5} = c → 3,249615362 ≈ 3,2$

Split the isosceles base in half to get two identical legs of 3,8.

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