Chemistry: The student placed 10 ml of pbcl2 (saturated solution) in the test tube and added a pinch of nacl. a white precipitate of pbcl2 formed. how will this affect the concentration of pb+2?

The student placed 10 ml of pbcl2 (saturated solution)

Ответ:

aeshaalhemri

14.01.2022

PbCl₂(aq) → Pb²⁺(aq) + 2Cl⁻(aq)

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

Pb²⁺(aq) + 2Cl⁻(aq) ⇄ PbCl₂(s)

At increase the concentration of chloride ions - concentration of lead ions decreases, the lead chloride is formed.

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Ответ:

hastlingc

14.01.2022

Chemistry

Concentration of $Pb^{2+}$ decreases

Explanation:

In a saturated solution of $PbCl_{2}$ , the following solubility equilibrium exist-

$PbCl_{2}\rightleftharpoons Pb^{2+}+2Cl^{-}$

Now, NaCl contains common ion $Cl^{-}$ . Therefore, concentration of $Cl^{-}$ increases in solution.

But, at a particular temperature, equilibrium constant remain constant. Therefore to keep equilibrium constant same $Pb^{2+}$ will reacts with excess $Cl^{-}$ to decrease concentration of $Cl^{-}$ .

Therefore concentration of $Pb^{2+}$ decreases.

Note: Equilibrium constant for the above equilibrium= $\left [ Pb^{2+} \right ]\left [ Cl^{-} \right ]^{2}$

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Ответ:

brittany7436

14.06.2020

Chemistry

They could add solar panels to help save energy and cost.

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The student placed 10 ml of pbcl2 (saturated solution) in the test tube and added a pinch of nacl. a white precipitate of pbcl2 formed. how will this affect the concentration of pb+2?

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