Chemistry: What is the theoretical yield of bismuth when 198 g of bi2o3 reacts with excess carbon as shown below? bi2o3 c(s) bi(s) + co(g) (not balanced)

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What is the theoretical yield of bismuth when 198

Serenitybella

02.01.2022

179.4306 g

Explanation:

Given that:

Mass of Bi_2O_3 = 198 g

Molar mass of Bi_2O_3 = 465.96 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{198\ g}{465.96\ g/mol}$

$Moles\ of\ Bi_2O_3= 0.4293\ mol$

From the balanced reaction,

$Bi_2O_3+3C\rightarrow 2Bi+3CO$

1 mole of Bi_2O_3 on reaction produces 2 moles of bismuth

So,

0.4293 mole of Bi_2O_3 on reaction produces 2 × 0.4293 moles of bismuth

Moles of bismuth = 0.8586 moles

Molar mass of bismuth = 208.9804 g/mol

So, mass of bismuth = Moles × Molar mass = 0.8586 × 208.9804 g = 179.4306 g

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