What is the volume occupied by .355 mole of nitrogen gas at stp?

Suppose Nitrogen Gas is acting Ideally, then According to Ideal Gas Equation, Pressure, Volume, moles and Temperature are related to each other as,

                                               P V  =  n R T

Solving equation for V,

                                               V  =  n R T / P    (1)
Data Given;
                   Volume to find  =  V  =  ?

                   Standard Pressure  =  P  =  1 atm

                   Standard Temperature  =  T  =  273 K

                   Moles Given  =  n  =  0.355 mol

Putting values in eq.1,

                      V  =  (0.355 mol × 0.0821 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm

                      V  =  7.95 L

Explanation:

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