What mass of water is need to dissolve 34.8 g of copper (ii) sulfate in order to prepare a 0.521 m solution?

419.2 g of water

Explanation:

0.521 = 0.521 moles of CuSO4 in 1000 ml (1 kg) of water

moles = mass/molar mass

34.8 g of CuSO4 = 34.8/159.6086 moles

                                 = 0.2180 moles

0.521 moles of CuSO4 is in 1 kg of water gives 0.521 M

Therefore, 0.2180 moles of CuSO4 in X kg of water will give 0.521 M

X  = 0.218/0.52

          = 0.4192 kg

                  = 419.2 g

Therefore, 419.2 g of water will be needed to dissolve 34.8 g of CuSO4 in order to prepare 0.521 molar solution.

In arithmetic sequence, let the first tern of the arithmetic sequence be, a, and the common difference, d, then the nth term, Tn, of the arithmetic sequence is given by:



For a linear function with y-intercept, c, and slope, m, the linear function is given by:



Comparing the equation of the arithmetic sequence and that of the linear function, we can see that y is compared to Tn, a is compared to c, m is compared to d, and x is compared to n - 1.

Therefore, the common difference in an arithmetic sequence is like the slope of a linear function as both are multiple of a variable.