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harleycochran2ovyt3n
10.07.2019 •
Chemistry
Which description is true of 0.02 m ca(oh)2 if ca(oh)2 completely dissociates in water? a. it’s a dilute strong acid. b. it’s a dilute strong base. c. it’s a dilute weak base. d. it’s a concentrated weak base. e. it’s a concentrated weak acid.
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Ответ:
B. It’s a dilute strong base.
Explanation:
1) Definition of acids and bases: as per Bronsted-Lowry model, an acid is a substance that donates hydrogen ions and a base is a substance that accepts hydrogen ions.
Ca(OH)₂ does not have hydrogen ions to donate, but it can accept hydrogen ions to form H₂O according to this equation: H⁺ + OH⁻ → H₂O.
Hence, Ca(OH)₂ is a base.
2) Definition of strong base: a strong base is a base that dissociates completely into metallic and hydroxide ions in aqueous solutions, while a weak base dissociates partially.
Hence, Ca(OH)₂ is a strong base.
3) Definition of dilute: it refers to a solution meaning that the substance is not pure and the concentration is low. Since, the solution the Ca(OH)₂ is 0.02 M means that it is dilute.
Therefore, we have found that the description of 0.02 M Ca(OH)₂ is that is is a dilute strong base (option B).
Ответ:
103.5 cm^3
Explanation: