Chemistry: You have a vinegar solution you believe to be 0.73 M. You are going to titrate 20.99 mL of it with a NaOH solution that you know to be 0.583 M. At what volume of added NaOH solution would you expect to see an end point

the property of air shown in the figure describe A.mass...

You have a vinegar solution you believe to be

josht7806

14.02.2022

The answer is "262.83 mL"

Explanation:

The equation for the reaction is :

$HA+ NaOH \longrightarrow NaA+H_2 O$

Calculating the moles of HA:

$=0.02099 \ LHA \times \frac{0.73 \ mol \ HA}{1 \ L HA}\\\\= 0.153227 \ mol HA$

Calculating the moles of NaOH:

$= 0.153227 \ mol \ HA \times \frac{1 \ mol\ NaOH}{1 \ mol \ HA}\\\\ = 0.153227\ mol \ NaOH$

Calculating the volume of the NaOH:

$=0.153227 \ mol \ NaOH \times \frac{1 \ L \ NaOH}{0.583 \ mol \ NaOH}\\\\= 0.262825043\ L \\\\ = 262.83 \ mL$

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