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Tyrant4life
16.04.2020 •
Computers and Technology
Create a Turing Machine in JFLAP (over the alphabet {a,b,#}) that takes a string with one # in it and swaps the strings on either side of the #. If the string is a legal start string then the machine halts pointing at the # when it's done. If it's not a legal start string then the machine should not accept the string (i.e. don't go to the halt state) but otherwise it can do whatever you like...
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Ответ:
4 GHz
Explanation:
Time taken for computer A to execute the program is = 10 secs
Given frequency of the clock for computer A is = 2 GHz
We know Clock period = 1 / frequency = 1 / 2 * 109 = 0.5 ns
Number of clocks requried to execute the program in computer A is
= Total Execution time / clock period = 10 / 0.5 * 10-9 = 20 * 109 clocks
Given Time taken for computer B to execute the program is = 6 secs
Given computer B requries 1.2 times as many clocks as computer A
implies number of clocks to execute program in computer B = 1.2 * 20 * 109 = 24 * 109
Here clock period of computer B = Total execution time / number of clocks
= 6 secs / 24 * 109
= 0.25 ns
Hence clock rate = frequency is = 1 / clock period = 1 / 0.25 ns = 4 GHz.