The drawing that would most likely show where a particular instrument is to be installed, and the elevation at which it is to be installed is the . Group of answer choices location drawing P

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Ответ:

Symonek

25.05.2020

Engineering

8.62m/s²

Explanation:

the particle is experiencing both translational and circular motion

v=4t²

$a_{t}$ = $\frac{dv}{dt}$ =8t

at t=1s, $\frac{dv}{dt}$ =8(1)=8m/s²

$a_{c}$ = $\frac{v^{2} }{r}$

at t=1, v= 4(1)² = 4m/s

$a_{c}$ =4²/5

$a_{c}$ =3.2m/s²

∴ magnitude of total acceleration, a

a= $\sqrt{a_{t} ^{2} + a_{c} {2} }$

a= $\sqrt{8^{2} +3.2^{2} }$

a= $\sqrt{64+10.24}$

a= $\sqrt{74.24}$

a=8.62m/s²

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