cthompson1107
04.09.2019 •
Mathematics
*1 a car is driving away from a crosswalk. the distance d (in feet) of the car from the crosswalk t
seconds since the car started moving is given by the formula d = t^2+3.5.
a. as the number of seconds since the car started moving
increases from 1 second to 3 seconds, what is the change
in the car's distance from the crosswalk?
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Ответ:
The change in the car's distance is 8 feet
Step-by-step explanation:
* Lets explain how to solve the problem
- A car is driving away from a crosswalk
- The distance d (in feet) of the car from the crosswalk t seconds
since the car started moving is given by the formula d = t² + 3.5
- The time increasing from 1 second to 3 seconds
- We need to now the change of the car's distance from the crosswalk
∵ The equation of the distance is d = t² + 3.5
∵ The time is 1 second
∴ d = (1)² + 3.5
∴ d = 1 + 3.5 = 4.5 feet
∵ The time is 3 seconds
∴ d = (3)² + 3.5
∴ d = 9 + 3.5 = 12.5 feet
∵ The change of the distance = d of 3 sec - d of 1 sec
∵ d of 3 sec = 12.5 feet
∵ d of 1 sec = 4.5 feet
∴ The change of the distance = 12.5 - 4.5 = 8 feet
∴ The change in the car's distance is 8 feet
Ответ:
56
Step-by-step explanation:
you do 209-153=56