1. m(4 + p) + p(3+ m) 2. 4r(3 + 4p) + 3p(8 -r)
3. (3 + 2h)(5 + 3h)
4. (3 + 4y)(5y - 1)
5. (2n - 3p)(3p - 2m)

Expand and simplify each of the following . Please give me the correct answer. Thanks

1. 4m + 2mp + 3p

2. 12r + 13pr + 24p

3. 6h^2 + 19h + 15

4. 20y^2 + 11y - 3

5. -9p^2 - 4mn + 6mp + 6np

Step-by-step explanation:

1. m(4 + p) + p(3+ m)

   4m + mp + 3p + mp

 4m + (mp + mp) + 3p

  4m + 2mp + 3p

2. 4r(3 + 4p) + 3p(8 -r)

  12r + 16pr + 24p + -3pr

  12r + (16pr - 3pr) + 24p

  12r + 13pr + 24p

3. (3 + 2h)(5 + 3h)

  3(5 + 3h) + 2h(5+3h)

  15 + 9h + 10h + 6h^2

  6h^2 + 19h + 15

4. (3 + 4y)(5y - 1)

  3(5y - 1) + 4y(5y - 1)

  15y - 3 + 20y^2 - 4y

  20y^2 + 11y - 3

5. (2n - 3p)(3p - 2m)

   2n(3p - 2m) + -3p(3p - 2m)

  6np - 4mn + -9p^2 + 6mp

  -9p^2 - 4mn + 6mp + 6np

Hope this helps!

Step-by-step explanation:

Given that according to the U.S. Census Bureau, the prob ability that a randomly selected household speaks only English at home is 0.81.

The probability that a randomly selected household speaks only Spanish at home is 0.12.

(a)  the probability that a randomly selected household speaks only English or only Spanish at home

= 0.81+0.12 = 0.93

(since these two are disjoint sets)

(b)  the probability that a randomly selected household speaks a language other than only English or only Spanish at home

= 1-0.93= 0.07 (remaining)

(c)  the probability that a randomly selected household speaks a language other than only English at home

=1-0.81=0.19

(d) Can the probability that a randomly selected household speaks only Polish at home equal 0.08? Why or why not?

Polish alone can never exceed 1-(0.81+0.12) i.e. 0.70

At most it can take values as 0.7 only

So no is the answer.