1. What is the equation of a line whose x-intercepts is 2 and y-intercepts is 1/3? 2. What is the equation of a line whose x-intercepts is 4 and y-intercepts is -1? I NEED IT NOW PLEASE

x + 6y - 2 = 0 ; - x + 4y + 4 = 0

Step-by-step explanation:

General form of equation :

x / a + y/b = 1

With x intercept = a ; y intercept = b

From the question :

X intercept = 2 ; y intercept = 1/3

x / 2 + y/ 1/3 = 1

x /2 + 3y / 1 = 1

Multiply through by 2

x + 6y = 2 ; x + 6y - 2 = 0

2)

x intercept = 4

y intercept = - 1

x / 4 + y/ - 1 = 1

(-x + 4y) / - 4 = 1

-x + 4y = - 4 ; - x + 4y + 4 = 0

im sorry i dont understand that

Step-by-step explanation: