2015 > Chapter 7 Chapter Test 7
You can model an arch at your school using the equation y = -0.8 (x– 6) (x+ 2), where x and y are
measured in feet. The X-axis represents the ground. Find the width of the arch at ground level.

11.6a + 880.2b - 477.2c

Step-by-step explanation:

Given:

length of the court = (5.8a+6.1b-3.6c) feet

width of the court = (434b-235c) feet

Since the court is said to be rectangular in shape :

The perimeter of a rectangle = 2(length + width)

Perimeter = 2(5.8a+6.1b-3.6c + 434b-235c)

Perimeter = 2(5.8a+6.1b+434b-3.6c-235c)

Perimeter = 2(5.8a + 440.1b - 238.6c)

Perimeter = 11.6a + 880.2b - 477.2c