arnold2619
04.05.2021 •
Mathematics
3x^2-12+(x-4)(2-x)-(x^2-4x+4)
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Ответ:
2(x^2 - 9x + 18)
18 * 1 = 18
(x - 6)(x - 3)
x - 6 = 0; x = 6
x - 3 = 0; x = 3
x = 6 and x = 3 are your zeroes.
I hope this helps!