tzartiger12
07.09.2019 •
Mathematics
4. find the equations of the following lines:
a. having slope of -2 and passing through the point (-4, 2)
b. parallel to y = 6x + 3 and passing through the point (-1, 13)
c. perpendicular to 3x – 5y = 5 and having an x-intercept of 3
d. passing through (-2, -6) and (4, 2)
e. having an x-intercept of -3 and a y-intercept of 6
this is frustrating me to no ! !
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Ответ:
Step-by-step explanation:
The general equation for a line is given by: y = mx + n (m: slope, n: y-intercept)
a)
given: m = -2, x = -4, y = 2
equation becomes: 2 = -2 * (-4) + n
solve for n: n = -6
solution: y = -2x - 6
b)
given: m = 6, x = -1, y = 13
equation becomes: 13 = 6 * (-1) + n
solve for n: n = 19
solution: y = 6x + 19
c)
given: perpendicular to: y = 3/5x - 1 => m = -5/3, x = 3, y = 0
equation becomes: 0 = (-5/3) * 3 + n
solve for n: n = 5
solution: y = -5/3x + 5
d) get the slope m from the two points.
given: m = Δy/Δx = 8/6 = 4/3, x = 4, y = 2
equation becomes: 2 = (4/3) * 4 + n
solve for n: n = -10/3
solution: y = (4/3)x - (10/3)
e)
given: point1 (-3,0), point2(0,6)
m = Δy/Δx = 6/3 = 2, x = 0, y = 6
equation becomes: 6 = 0 + n
solve for n: n = 6
solution: y = 2x + 6
Ответ: