5.02

based on the figure below what is the value of x

3

9

12

15

The original number is 245.

Step-by-step explanation:

Let A be the hundreds digit of the original number, B be the tens digit of the original number, and C be the units digit of the original number.

We know from the first two sentences in the problem that:

C = 5

A + B + C = 11

Substituting the value of C, we get:

A + B + 5 = 11

A + B = 6

In the third sentence, we are told that when the number is added to the reverse of itself, the sum of the two numbers is 787. Expressed mathematically:

100A + 10B + C + A + 10B + 100C = 787

Where (100A + 10B + C) gives the value of the original number and (A + 10B + 100C) gives the value of the number when reversed. Simplified, we get:

101A + 20B + 101C = 787

Rewriting the "A + B = 6" equation from above as B = 6 - A, we substitute (6 - A) into the equation above for B and substitute 5 for C (because we know C = 5):

101A + 20(6 - A) + 101 * 5 = 787

101A + 120 - 20A + 505 = 787

81A + 625 = 787

81A = 162

A = 2

Now that we have A, we can get B using A + B = 6:

2 + B = 6

B = 4

To summarize:

A = 2

B = 4

C = 5

So the original number must be 245.