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eggyhz1980
11.10.2019 •
Mathematics
"a 23kg kg child goes down a straight slide inclined 38∘ above horizontal. the child is acted on by his weight, the normal force from the slide, kinetic friction, and a horizontal rope exerting a 30n force as shown in the figure.(figure 1)
how large is the normal force of the slide on the child? "
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Ответ:
Normal force = component of child's weight that acts normal to slide - 30 sin 38°
Normal force = mg(cos 38°) - 30(sin 38°)
Normal force = (23)(9.8)(cos 38) - 30(sin 38)
= 178 - 18.5
= 159.5 N
159.5 N is the answer.
Ответ:
8742
Step-by-step explanation:
838473