A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped into a container of boiling water (100oC). If the temperature of the sphere increases 15o in 9 seconds, find the temperature of the ball after 18 seconds in the boiling water. (Assume the sphere obeys Newton's Law of Cooling.)

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

We'll solve for k

Divide both sides by -5

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

A] from the box plots representing the battery brands we shall have the median as follows:
brand x- median is 13
brand y- median is 16

b]  what is range for each data set?
range is given by:
maximum-minimum 
brand x
maximum=16
minimum =11
range=16-11=5
brand y
maximum=18
minimum=10
thus
range=18-10=8
c] what is the interquartile range for each data set?
iqr=[3rd quartile]-[1st quartile]
brand x:
3rd quartile=14.5
1st quartile=12
iqr=14.5-12=2.5
brand y
3rd quartile=17
1st quartile=15
iqr=17-15=2
d] i'd recommend brand y because the average life is greater than brand x. that means it lasts more as compared to the latter