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adriannamartinez000
12.08.2020 •
Mathematics
A circular hall has a hemispherical roof.
The greatest height is equal to the
inner diameter. If the capacity of
the hals is
the
floor is.
43510 m^3
then
area
of the
Solved
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Ответ:
Area=1,288.88m²
Step-by-step explanation:
A circular hall(big room) has a hemispherical roof.The greatest height is equal to the inner diameter.Find the area of the floor,given that the capacity of the hall is 43510 cubic meter
Solution
let
diameter = D
radius,r = D/2
Greatest height = D
height of cylindrical part (h)= D-r = r
radius of cylindrical part = r
area of floor = πr²
volume = volume of cylindrical part + volume of hemispherical part
= πr²h + 2/3 πr³
Recall h=r
volume = πr³ + 2/3 πr³
43510=5/3πr³
Make r the subject
r=3√(43510*3)/5π
=3√(130,530/15.7
=3√8,314.01
=20.26
Area of floor = πr²
=3.14*(20.26)²
=3.14*410.47
=1,288.88m²
Ответ:
The first and third options are correct.
Step-by-step explanation:
Hope this helps!