A company is thinking about offering employee wellness classes during operational hours to boost production. They want to perform an experiment to see if employees attending these classes improve their quality of work. What is the best way to randomly choose a group of employees to attend these classes?​

Use a computer software program that will pick employees randomly from a list.

Use a computer software program that will pick employees randomly from a list

Step-by-step explanation

i took the test :)

Using the normal distribution, it is found that the area of the shaded region is of 0.7233.

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Normal Probability Distribution

Z-score formula is used, considering a measure X, mean and standard deviation .

Each z-score has an associated p-value, which represents the percentile of the measure X.The area between two z-scores is the p-value of the greater z-score subtracted by the p-value of the smaller z-score.

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Looking at the z-table, we get that:

z = 1.25 has a p-value of 0.8944.z = -0.95 has a p-value of 0.1711.

0.8944 - 0.1711 = 0.7233.

The area of the shaded region is of 0.7233.

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