Mathematics: A division of a company has over 200 employees, 40% of which are male. Each month, the company randomly selects 8 of these employees to have lunch with the CEO. What are the mean and standard deviation of the number of males selected each month? You may round your answers to the nearest tenth. mean:? males standard deviation:? males

A division of a company has over 200 employees, 40%

luigiguitar8668

24.01.2022

$\mu_p=3.2\\\\\sigma_p=0.2$

Step-by-step explanation:

-The number of males in the company is:

$Males, n=\%\ Males\times Total\\\\=0.4\times 200\\\\=80$

#Given the proportion of males in the population is 40%(p=0.4) and the sample size, n=8

-The mean and standard deviation of a sample proportion is calculated as follows:

$\mu=np\\\\=0.4\times 8\\\\\\\\=3.2\\\\\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.4(1-0.4)}{8}}\\\\\\\\=0.1732\approx0.2$

Hence, the mean of males is 3.2 and the standard deviation is 0.2

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lilchannelll4125

17.05.2020

64x^18y^6

Step-by-step explanation:

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