A dog is standing 5 feet from the base of a tree, looking up at a cat that has climbed 16 feet up the tree. What is the angle of elevation from the point the dog is standing on the ground to the cat?

x=72.6

Step-by-step explanation:

use inverse trig because your finding a missing angle. use tan because you haved opp/adj

tan-1=(16/5)

x=tan-1(16/5)

*use a calculator

x=72.6

CI 96 %  =  ( - 0.1128  ; 0.0728 )

CI 95%  =  ( - 0.1087 ; 0.6878 )

The two intervals contain 0 value therefore we can support that there is not statistics difference between the two groups with confidence level of 96 % and  95%

Step-by-step explanation:

Boys sample:

sample size   n₁  = 200

x₁  number of boys saying their parents are very involved in their lives

=  93

p₁ = x₁/n₁   =  93/200  =  0.465  then  q₁ =  1  -  p₁   q₁ = 1 - 0.465  q₁ = 0.535

Girls sample

sample size   n₂  = 300

x₂  number of girls saying their parents are very involved in their lives

=  172

p₂  =  x₂/n₂  =  172/ 300  =  0.573 then  q₂ = 1 -0.573  q₂ =  0.427

CI 96 %      α = 4 %  α = 0.04    α/2 = 0.02  

p₁  -  p₂  =  0.465 -  0.573  = - 0.168

CI 96 %   =  (  p₁  -  p₂ ) ±  z(c) * SE

z(c)  for  α  =  0.02       z(c)  =  - 2.05

SE = √ (p₁*q₁)/n₁  +  (p₂*q₂)/n₂

SE = √ ( 0.465*0.535)/200  +  (0.573*0.427)/300

SE =  √  0.00124  +  0.000815    

SE =  √  0.00205

SE =   0.0453

CI 96 %  =  (  -0.02  ±  ( 2.05 * 0.0453 ) )

CI 96 %  =  (  -0.02  ±  ( 0.0928 ))

CI 96 %  =  ( - 0.1128  ; 0.0728 )

a) CI 95%  α =  5 %   α = 0.05     α/2 =  0.025

SE = 0.0453

z(c) for  0.025 is from z-table   z(c)  =  1.96

CI 95%  =  ( - 0.02 ±  1.96 * 0.0453)

CI 95%  =  ( - 0.02 ± 0.08878 )

CI 95%  =  ( - 0.1087 ; 0.6878 )