katlyn10289

20.08.2020 •

Mathematics

A hiker walks 3.2 km on a bearing of 120 and then takes a bearing of 055 and walks 6 km. The bearing he must take to return directly to the start is: A013
B077
C235
D257
E330

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Ответ:

savannahvargas512

02.05.2020

Mathematics

f(a)=1+5a^2

f(a+h)=1+5a^2+10ah+5h^2

$\frac{f(a+h)-f(a)}{h}=10a+5h$

Step-by-step explanation:

We are given f(x)=1+5x^2 .

Find f(a) . All this means is replace in f(x)=1+5x^2 with .

f(x)=1+5x^2

f(a)=1+5a^2

Find f(a+h) . All this means is replace (a+h) in f(x)=1+5x^2 with (a+h) .

f(x)=1+5x^2

f(a+h)=1+5(a+h)^2

f(a+h)=1+5(a+h)(a+h)

f(a+h)=1+5(a^2+2ah+h^2)

f(a+h)=1+5a^2+10ah+5h^2

Find $\frac{f(a+h)-f(a)}{h}$ . So we got to put some parts together; the parts above:

$\frac{f(a+h)-f(a)}{h}$

$\frac{(1+5a^2+10ah+5h^2)-(1+5a^2)}{h}$

Now in the first ( ) I see 1+5a^2 and in the second ( ) I see 1+5a^2, so this means you have (1+5a^2)-(1+5a^2) which equals 0.

$\frac{10ah+5h^2}{h}$

Now assuming h is not 0. we can divide top and bottom by h.

$\frac{10a+5h}{1}$

10a+5h

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A hiker walks 3.2 km on a bearing of 120 and then takes a bearing of 055 and walks 6 km. The bearing he must take to return directly to the start is: A013B077C235D257E330