A parabola has x-intercepts of (2, 0) and (-4, 0) and has a leading coefficient of 1. What is the equation of the parabola in standard form? *

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  y = x^2 +2x -8

Step-by-step explanation:

For x-intercepts p and q, factors of the parabola's equation are (x-p) and (x-q). Since the leading coefficient is 1, those are the only factors.

  y = (x -2)(x -(-4))

  y = (x -2)(x +4) = x(x +4) -2(x +4) . . . . use the distributive property

  y = x^2 +4x -2x -8 . . . . use the distributive property again

  y = x^2 +2x -8 . . . . . . . .equation in standard form