A section of a roof is shaped like a triangle. The base of the triangle is 17 feet and the height is 9 feet. What is the area of triangle section?

Area of Triangle Section= 76.5

Step-by-step explanation:

Area of a triangle= A=

A=

A=

A=76.5

See the attached figure which represents the problem.

Angles GJH and JHI are inscribed angles

Given: ∠GJH = 0.5a  and ∠JHI = 0.5b ⇒ inscribed angle theorem

So, the angle JHI is an exterior angle of ΔGJH

AS, the measure of the exterior angle is equal to the sum of the sum of the remote interior angles

So, ∠JHI = ∠GJH + ∠JGI ⇒ by substitution property

∴ 0.5 b = 0.5a + ∠JGI

∴ ∠JGI = 0.5b - 0.5a ⇒ take 0.5 as a common

∠JGI = 0.5 ( b - a ) ⇒ by distributive property.

So, m∠JGI = One-half(b – a)