A spittlebug jumps into the air with an initial vertical velocity of 10 feet per second. The spittle bug reaches its maximum height after 0.3125 seconds. How high can it jump?

3.125 ft

Step-by-step explanation:

Parameters given:

Initial velocity of spittlebug, v = 10 ft/s

Time taken to reach maximum height, t = 0.3125 s

To find the maximum height reached by the spittlebug we simply apply the formula for speed.

Speed is the time rate of displacement, in other words, how fast an object changes its position in a given time.

Speed = distance / time

Distance will then be:

Distance = speed * time

D = v * t

Hence, the maximum height reached by the spittlebug is:

D = 10 * 0.3125 = 3.125 ft

The answer for x is 32 degrees while y is 35.

Step-by-step explanation: The reason for this is because two lines right across each other are vertical and are equal. For example 32 degrees is across x therefore x equals 32 degrees also. The way we find y is by subtracting all the other angles and then finding the measurement of the angle. The equation would look like this 180-90-32-23=35. We got the 90 degrees from the angle O because it is right across a 90 degree angle there making it equal to the other angle. Hope this helps and thank you for brainliest!