A square is drawn in the coordinate plane, with vertices as shown in the diagram. Then the square undergoes
a rigid motion.
The function that describes the rigid motion could be
(x, y)→
A. (2x, y)
B. (X-3, y)
C. (x, -2y)
D. (X,3)

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Ответ:

AnaiyaKirksey8

01.06.2022

Mathematics

The image of P(x,y) = (2,-3) is P'(x,y) = (-2, -3) .

Step-by-step explanation:

According to this statement, we need to find the image of a given point by reflection with respect to the y-axis. The reflection can be done by following operation:

$P(x,y) = (x, y) \to P'(x,y) = (-x, y)$ (1)

Where:

P(x,y) - Original point.

P'(x,y) - Reflected point.

If we know that x = 2 and y = -3 , then the reflecting point is:

P'(x,y) = (-2, -3)

The image of P(x,y) = (2,-3) is P'(x,y) = (-2, -3) .

The point (2, -3 ) is reflected in the line x = 0 find the image

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A square is drawn in the coordinate plane, with vertices as shown in the diagram. Then the square undergoes a rigid motion. The function that describes the rigid motion could be (x, y)→ A. (2x, y) B. (X-3, y) C. (x, -2y) D. (X,3)