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dooboose15
11.02.2020 •
Mathematics
A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups as they could. The 10 randomly selected students averaged 15 pushups per person with a standard deviation of 9 pushups.Suppose the distribution of the population of number of pushups that can be done is approximately normal. The 95% confidence interval for the true mean number of pushups that can be done is
a. 13.02 to 16.98.
b. 8.56 to 21.40.
c. 11.31 to 18.55.
d. 5.75 to 24.25.
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Ответ:
b. 8.56 to 21.44
Step-by-step explanation:
Let
be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean :![\overline{x}=15](/tpl/images/0507/1128/c3fd6.png)
Sample standard deviation :![s=9](/tpl/images/0507/1128/efaad.png)
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is
Confidence interval for
is given by :-
Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Ответ:
1 dvd and 4 cds
Step-by-step explanation:
If you have $65.00 and 1 dvd costs $15.00 that leaves you with $50.00 and each CD costs $12.00 just multiply by 12s until you get to 50 or close so there you can buy 4 CDs and have 2$ left.