miriammayo12345
07.04.2020 •
Mathematics
A whole number from 1 to 15 inclusive is picked at random.
E = Whole numbers from 1 to 15 inclusive
M = Multiples of 3
By correctly completing the
F = Factors of 24
(Venn diagram)
a) What is the probability
that the number chosen
is a multiple of 3 given
that it is a factor of 24?
b) What is the probability
that the number chosen
is a factor of 24 given
that it is a multiple of 3?
Solved
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Ответ:
The probability for the scenario in a and b are; 1/5 and 1/5 respectively.
The set of numbers which make up the universal set are: {1, 2, 3 ,4 ,5 ,6 ,7, 8, 9, 10, 11, 12, 13, 14, 15}
M = 3, 6, 9, 12, 15F = 1, 2, 3, 4, 6, 8, 12.The numbers in the common to both subsets M and F are: 3, 6, 12
a) The probability that the number chosen
is a multiple of 3 given that it is a factor of 24 is therefore;
P(M & F) = 3/15P(M & F) = 1/5.b) the probability that the number chosen is a factor of 24 given that it is a multiple of 3 is therefore;
P(F & M) = 3/15P(F & M) = 1/5Read more:
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Ответ:
Explanation:
The figure attached shows the Venn diagram for the given sets.
a) What is the probability that the number chosen is a multiple of 3 given that it is a factor of 24?
From the whole numbers 1 to 15, the multiples of 3 that are factors of 24 are in the intersection of the two sets: 3, 6, and 12.
There are a total of 7 multiples of 24, from 1 to 15.
Then, there are 3 multiples of 3 out of 7 factors of 24, and the probability that the number chosen is a multiple of 3 given that is a factor of 24 is:
3/7b) What is the probability that the number chosen is a factor of 24 given that it is a multiple of 3?
The factors of 24 that are multiples of 3 are, again, 3, 6, and 12. Thus, 3 numbers.
The multiples of 3 are 3, 6, 9, 12, and 15: 5 numbers.
Then, the probability that the number chosen is a factor of 24 given that is a multiple of 3 is:
3/5Ответ: