A wire that is 80 centimeters long is shown below. The wire is cut into two pieces, and each piece is bent and formed into the shape of a square. 80 cm wire Suppose that the side length (in centimeters) of one square is x cm. Express the perimeter of the big square in terms of x. (1 point)

The perimeter of the second(big) square =

Step-by-step explanation:

From the information given:

The length of the piece of the wire  = 80 cm

When being cut into two pieces;

the length of the first wire = x

Then the length of the second(big) wire will be = 80 - x

However, when each piece is bent to a square shape

The length of one side of the first square =

The length of one side of the second(big) square;

Area of a square = l² ( where l is the length of the sides)

For the first square

A₁ =

A₁ =

The area of the second(big) square is:

A₂ =

A₂ =

The perimeter of the first square =

The perimeter of the second(big) square =

The k-th root's inverse function is raising to the k-th power.

So, if we raise the k-th root of some number x to the k-th power, we have applied a function and its inverse to x, and we must get x itself as output:

So, in our case, we have