Mathematics: A3 + b3 = (a + b)(a2 - ab + b2) Use the identity of the sum of two cubes to factor 8q6r3 + 27s6t3. what is a? what is b?

A3 + b3 = (a + b)(a2 - ab + b2) Use the identity

Ответ:

Glamis856

10.02.2022

Mathematics

Factors of 8q^6r^3 + 27s^6t^3 are (2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)

a is 2q^2r

b is: 3s^2t

Step-by-step explanation:

We need to factor 8q^6r^3 + 27s^6t^3

$8q^6r^3 + 27s^6t^3\\=(2q^2r)^3+(3s^2t)^3\\Applying \ formula: a^3 + b^3 = (a + b)(a^2 - ab + b^2)\\=(2q^2r+3s^2t)((2q^2r)^2-2(2q^2r)(3s^2t)+(3s^2t)^2)\\=(2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)$

So, Factors of 8q^6r^3 + 27s^6t^3 are (2q^2r+3s^2t)(4q^4r2-12q^2rs^2t+9s^4t^2)

What is a? a is 2q^2r

What is b? b is: 3s^2t

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A3 + b3 = (a + b)(a2 - ab + b2) Use the identity of the sum of two cubes to factor 8q6r3 + 27s6t3.
what is a?
what is b?

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