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MINDYDELANO
23.06.2019 •
Mathematics
A4- figure passcode is to be formed from 3 letters of the alphabet and 3 digits. how many passcodes can be formed if: a. the first figure is a letter and the rest are digitsb. the first and last figures are digits and in the middle is letter dc. the digits and alphabets are alternate
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Ответ:
A. 81
B. 9
C. 81
Step-by-step explanation:
We have that,
Number of figures in the password = 4.
Number of letters used = 3
Number of digits used = 3.
A. The first figure is a letter and the rest are digits
As, the first figure is a letter, so its position is fixed and the other figure are the numbers.
Since, there can be any possibility out of 3 letters and 3 digits,
Number of ways to form the pass-code = 3 × 3 × 3 × 3 = 81
Thus, there are 81 ways in this case.
B. The first and last figure are digits and in the middle is the letter D.
So, we have the case, _ D D _ with the blanks taking digits.
Since, there can be any possibility out of 3 digits,
Number of ways to form the pass-code = 3 × 1 × 1 × 3 = 9
Thus, there are 9 ways in this case.
C. The digits and alphabets are alternate.
As, there are 3 options for letters and 3 options for digits.
Number of ways to form the pass-code = 3 × 3 × 3 × 3 = 81
Thus, there are 81 ways in this case.
Ответ:
Just say what you did in your math equation