Aball is kicked upward with an initial velocity of 68 feet per second. the ball's height, h (in feet), from the ground where it is measured in seconds. how much time does the ball take to reach its highest point? what is its height at this point?

72.25 ft.

Step-by-step explanation:

When the ball would reach the maximum height, its velocity would be zero. Acceleration due to gravity would act downwards = -32 ft/s²

Using the first equation of motion, time can be calculated as:

v - u = a t

⇒ 0-68 ft/s = - 32 ft/s²× t

⇒t = 2.125 s

The ball would take 2.125 s to its highest point.

Using the third equation of motion, height can be calculated as:

Thus, its height would be 72.25 ft.

1). 7

2). 9

3). 6

Step-by-step explanation:

Given function is f(x) = x² + 7

From the given table,

1). Average rate of change of the function is represented by,

Average rate of change = =

Between x = 2 and x = 5,

Average rate of change =

                                         = 7

2). Between x = 3 and x = 6,

Average rate of change =

                                        = 9

3). Between x = 2 and x = 4,

Average rate of change =

                                        = 6