Abox contains 3 red, 2 white, and 5 blue beads, each of which is a solid color. miguel will randomly remove 1 bead from the box, record the color of the bead, and return the bead to the box. miguel will complete this process 50 times. how many times should miguel expect to record a bead color that is not white?

For every 10 it is 8/10 chance that it is NOT white.

So, if drawn 50 times...

8/10 x 50/1 =
8 x 50 = 400
10 x 1 = 10
400 / 10 = 40

40/50

He should expect to record a bead that is not white 40 times.

I haven’t done probability in awhile so I’m sorry if this is wrong :( Hopefully it’s right

The number of times miguel could expect to record a bead color that is not white is:

                                  40

Step-by-step explanation:

It is given that:

A box contains 3 red, 2 white, and 5 blue beads.

This means that there are a total of 10 beads in the box.

( since, 3+2+5=10 beads)

Now, miguel will randomly remove 1 bead from the box, record the color of the bead, and return the bead to the box. He performs this process 50 times.

Hence, the expected number of times of getting a non-white bead is:

 Probability of non-white bead×50

Now, the probability of getting a non-white bead= 8/10

( since there are 8 beads which are non-white i.e. 3 red plus 5 blue beads out of a total of 10 beads )

Hence, the number of times he could expectedly get a non-white bead is:

  (8/10)×50=40

3/4 cups of flour and 1/8 cups of toppings