Abullet is fired straight up from a bb gun with initial velocity 1,120 feet per second at an initial height of 8 feet. use the formula h=−16t2+v0t+8 to determine how many seconds it will take for the bullet to hit the ground. that is, when will h=0

Bullet will hit the ground after 70 seconds.

Step-by-step explanation:

A bullet is fired straight up from a BB gun with initial velocity 1120 ft/s at an initial height of 8 ft. Using the value of velocity the equation becomes:

h(t)= -16t² + 1120t + 8

We need to find time when bullet hit the ground.  

As we know when bullet hit the ground height would be 0  

So, we set h=0 and solve for t .

0 = -16t² + 1120t + 8

Using quadratic formula:

Since negative value of the time is not possible, we conclude that the bullet will hit the ground after 70 seconds.

CE = 3

Step-by-step explanation:

Given:

AE = 3

EB = 4

CE = x

ED = x + 1

Required:

CE

Solution:

First we need to determine the value of x by generating am equation as follows:

CE × ED = AE × EB (Interacting Chords Theorem)

Substitute

x × (x + 1) = 3 × 4

x² + x = 12

Subtract 12 from each side

x² + x - 12 = 12 - 12

x² + x - 12 = 0

Factorize to find the value of x

x² + 4x - 3x - 12 = 0

x(x + 4) -3(x + 4) = 0

(x - 3)(x + 4) = 0

x - 3 = 0

x = 3

Or

x + 4 = 0

x = -4

Let's use the positive value of x

CE = x = 3